![]() (xi) Thus the final position, nature and size of the image A'B' are: It is found that CB' = 3.3 cm and A'B' = 0.7 cm. (ix) Now AB', represents the real, but inverted image of the object AB. (viii) Draw AB', perpendicular to the principal axis from A'. (vii) Let the two lines starting from A meet at A'. (vi) Draw a line from A to C (centre of the lens), which goes straight without deviation. (v) Draw a line AD parallel to principal axis and then, allow it to pass straight through the focus (F') on the right side of the lens. (iv) Draw an arrow AB of height 1 cm on the left side of lens at a distance of 5 cm from the lens. (iii) Mark two foci F and F' on two sides of the lens, each at a distance of 2 cm from the lens. (i) Draw a horizontal line to represent the principal axis of the convex lens. Therefore, on this scale 5 cm high object, object distance of 25 cm and focal length of 10 cm can be represented by 1 cm high, 5 cm and 2 cm lines respectively. As the distances given in the question are large, so we choose a scale of 1: 5, i.e., 1 cm represents 5 cm. Thus, object is placed at a distance of 6 cm × 5 = 30 cm from the lens.Ĭonverging lens means a convex lens. (viii) Draw a line AB, perpendicular (downwards) from A to meet the principal axis at B. (vii) Draw a line CA', backwards, so that it meets the line from D parallel to principal axis at A. (vi) Draw a line A'B', perpendicular to principal axis from B'. (v) Draw a line AD, parallel to principal axis. (iv) Join any point D (nearly at the top of lens) and F by a dotted line. (iii) Mark points F and B on the left side of lens at a distance of 3 cm and 2 cm respectively. ![]() (ii) Draw a convex lens, keeping principal centre (C) on the principal axis. (i) Draw the principal axis (a horizontal line). Image distance, v = - 10 cm ĭrawing the ray diagram: Using a scale of 1: 5, we get v = - 2 cm, f = - 3 cm.
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